0=4p^2-2p-20

Solution for 0=4p^2-2p-20 equation:

0=4p^2-2p-20

We move all terms to the left:

0-(4p^2-2p-20)=0

We add all the numbers together, and all the variables

-(4p^2-2p-20)=0

We get rid of parentheses

-4p^2+2p+20=0

a = -4; b = 2; c = +20;
Δ = b2-4ac
Δ = 22-4·(-4)·20
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-18}{2*-4}=\frac{-20}{-8}
=2+1/2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+18}{2*-4}=\frac{16}{-8}
=-2
$